2x^2+8x-9604=0

Solution for 2x^2+8x-9604=0 equation:

2x^2+8x-9604=0

a = 2; b = 8; c = -9604;
Δ = b2-4ac
Δ = 82-4·2·(-9604)
Δ = 76896
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{76896}=\sqrt{144*534}=\sqrt{144}*\sqrt{534}=12\sqrt{534}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-12\sqrt{534}}{2*2}=\frac{-8-12\sqrt{534}}{4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+12\sqrt{534}}{2*2}=\frac{-8+12\sqrt{534}}{4}
$